RIEMANN'S ANALYTIC EXTENSION DISPROVED
James Constant
math@coolissues.com
Since antiquity, mathematicians have labored to find and apply prime numbers. These numbers extend from 1 to infinity. The Prime Number Theorem (PNT) tells us that the number of primes ox in the number interval x is approximately x/lnx. The PNT was first conjectured by Gauss and Legendre around 1800 and was proven by Hadamard and independently by Poussin in 1859. The PNT is written simply as ox~x/lnx and saying that ox is asymptotic to x/lnx as xtº.1
Proof of the PNT was one of the great achievements of analytic number theory. The next step was to reduce or eliminate its approximation. Riemann attacked the problem using a formula devised in 1737 by Euler which states that for every real x>1
which extends from Euler's x>1 domain to the larger domain x>0 and provides zeros in the strip 0<x<1. In 1859, Riemann proved that f(s), satisfies a functional equation which led to the theorem that all the zeroes of, except those at s=-2,-4,-6, . . . , lie in the strip of the s-plane for which 0<x<1 where x is the real part of s. Riemann conjectured that all the zeroes in the strip should lie on the line x= ½. Attempts to prove or disprove this conjecture have generated a vast and intricate department of analysis, especially since Hardy (1914) proved that f(s), has an infinity of zeroes on x=½.2 The question is still open in 2010. A prize is available to prove or disprove RH.3
Riemann's analytic extension leads to a number of obvious inconsistencies. First, the equality between the sum and product in Riemann's zeta function (2) is unproven. A comparison of series (1) and (2) leads to the impossibility f(s)=f(x). Since all primes pn>1 the analytic extension to interval 0<x<1 is irrelevant to determining primes. In interval x>1, the analytic extension would require replacing real prime numbers pn with imaginary ones pn+jpn' in product (2) thus making (2) invalid.
Second, Riemann's zeta function (2) converges conditionally which allows more than one value for its sum. The sum of a conditionally convergent series can be changed by a suitable rearrangement of the terms of the series. It can be made to converge to any number including zero and can even be made to diverge.4 This is not possible for absolutely converging series. Thus, using zeta function (2), one can prove5 or disprove RH. A vast number of proofs and disproofs now crowd mathematical analysis.6
2 E.T. Bell, The Development of Mathematics, Dover Publications, New York 1972. page 315.
3 Enrice Bombieri's The Riemann Hypothesis (Clay Mathematics Institute) at http://www.claymath.org/prize_problems/riemann.htm
4 e.g. see R. Courant, Differential and Integral Calculus, Interscience Publishers, Inc. New York 1947 Vol I pages 372-375
5 See Proof of Riemann's Hypothesis at http://www.coolissues.com/mathematics/Riemann/riemann.htm
6 See Attempts to Prove Disprove the Riemann Hypothesis at http://en.wikipedia.org/wiki/Riemann_hypothesis#CITEREFWatkins2007
Copyright 2009 by James Constant
By the same author: http://www.coolissues.com/mathematics/sameauthor.htm